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2 years ago

If a quadratic equation has a real root, what do you know about the other roots of the equation? Explain.

Mathematics

1 answer:

notsponge [240]2 years ago

7 0

Answer:

A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:

1) The other root is also a real number, but a different number

2) Its a repeated root, so the other root is the same number.

The other root cannot be a complex number as its not possible for one root to be real and other to be complex. Either no root will be complex or both will be complex roots.

Following are 3 possibilities for the roots of a quadratic equation:

2 Real and Distinct roots
2 Real and Equal roots
2 Complex roots

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Divide £50 in the ratio of 1:4

NikAS [45]

Answer=10:40

Explanation:

Don’t know how to type the symbol in font of the 50 so I will substitute
£50=$50

So 1:4
Add it up
1+4=5

So 5 total units
$50=5
Divided by 5
$10=1 units

So 1:4=10:10 times 4=10:40

6 0

3 years ago

Can you guys help please will mark brainliest answer.I need help on 24 and 28

frutty [35]

24) All percents are numbers with the decimal moved 2 to the right. So if you have 275%, move the decimal to the left twice to get a factor of 2.75. that means that the puppy is 2.75 times heavier at 4 months than it was at 2 months. Since you need the answer as a mixed fraction, your answer is;
$2.75=2+\frac{3}{4}=2~\frac{3}{4}$

28) If 6 of 75 trees are 30+ feet tall and you need to know how many are under, subtract 6 from 75 to get (75 - 6) = 69 trees under 30ft tall.
You're looking for the percent of trees under 30ft tall, so divide the number of trees <30ft by the total number of trees to get;
$\frac{69}{75}= .92$
Move the decimal 2 to the right to get 92%.
Your answer is that 92% of trees is under 30ft.

3 0

3 years ago

What are the possible values of x in 2x^2-8=10

Dimas [21]

Answer:

3, -3

Step-by-step explanation:

4 0

2 years ago

Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar

xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ $_{e}^2$ → $S_{e} ^{2}$ ), you have to use the following formula: