Answer:
∠ C = ∠BCD = 30°
Step-by-step explanation:
∠ EDF = ∠GFC = 110° [ corresponding angles ]
Now consider triangle BCF
∠FBC + ∠ABC = 180° [ straight line angle ]
∠FBC + 100° = 180°
∠FBC = 180 - 100 = 80°
∠BFC + ∠GFC = 180° [ straight line angle ]
∠BFC + 110° = 180°
∠BFC = 180 - 110 = 70°
Sum of angles of triangle is 180°
Therefore , in triangle BCF
That is ,
∠F + ∠B + ∠ C = 180°
70° + 80° + ∠C = 180°
∠C = 180 - 150 = 30°
we can use height formula
where
h(t) is the height after t seconds
v is velocity
h(0) is initial height
g is acceleration due to gravity
we know that
g=32 ft/s^2
we have
v=18.5ft/s
h(0)=4.5ft
so, we can plug these values
and we get
now, we have to find time when object will hit the ground
and we know that object will hit the ground when height becomes 0
so, we can set h(t)=0
and then we can solve for t
we can use pythagoras theorem
..............Answer