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Alenkasestr [34]
3 years ago
14

Complete the table for the given rule. Rule: Y = X + 8X | Y2. _0. _4. _​

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
5 0

Y=x+8

Table

\boxed{\begin{array}{c|c}\bf x&\bf y\\ \rm 2&\rm 10\\ \rm 0&\rm 8\\ \rm 4&\rm 12\end{array}}

How?

x=2

  • y=2+8=10

x=0

  • y=0+8=8

x=4

  • y=4+8=12
34kurt3 years ago
4 0

Answer:

\large\begin{array}{| c | c |}\cline{1-2} x & y \\\cline{1-2} 2 & 10 \\\cline{1-2} 0 & 8 \\\cline{1-2} 4 & 12 \\\cline{1-2}\end{array}

Step-by-step explanation:

Given rule:

y=x+8

The rule tells us that to the corresponding y-values, simply substitute the given value of x into the given rule:

x=2 \implies y=2+8=10

x=0 \implies y=0+8=8

x=4 \implies y=4+8=12

Therefore, the completed table is:

\large\begin{array}{| c | c |}\cline{1-2} x & y \\\cline{1-2} 2 & 10 \\\cline{1-2} 0 & 8 \\\cline{1-2} 4 & 12 \\\cline{1-2}\end{array}

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A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible o
Agata [3.3K]

Answer:

\begin{array}{cccccc}X&0&1&2&3&4\\Pr&\dfrac{1}{16}&\dfrac{1}{4}&\dfrac{3}{8}&\dfrac{1}{4}&\dfrac{1}{16}\end{array}

Step-by-step explanation:

A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible outcomes: BBBB, BBBG, BBGB, BGBB, GBBB, BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, BGGG, GBGG, GGBG, GGGB, and GGGG.

Let X represent the number of children that are girls. Then

1. When X=0, there is one possible outcome BBBB. So

Pr(X=0)=\dfrac{1}{16}

2. When X=1, then there are 4 possible outcomes GBBB, BGBB, BBGB, BBBG, so

Pr(X=1)=\dfrac{4}{16}=\dfrac{1}{4}

3. When X=2, then there are 6 possible outcomes BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, so

Pr(X=2)=\dfrac{6}{16}=\dfrac{3}{8}

4. When X=3, then there are 4 possible outcomes GGGB, GGBG, GBGG, BGGG, so

Pr(X=3)=\dfrac{4}{16}=\dfrac{1}{4}

5. When X=4, then there is one possible outcome GGGG, so

Pr(X=4)=\dfrac{1}{16}

Now, the probability distribution table is

\begin{array}{cccccc}X&0&1&2&3&4\\Pr&\dfrac{1}{16}&\dfrac{1}{4}&\dfrac{3}{8}&\dfrac{1}{4}&\dfrac{1}{16}\end{array}

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4 years ago
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Don't guess!
MrRissso [65]

Answer:

C

Step-by-step explanation:

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gladu [14]

The answers to the question are:

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<h3>a. How to determine the service charge rate for the month of October</h3>

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124600/8900

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Which shows the graph of the solution set of x + 2y &gt; 4?
nata0808 [166]

we have

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The answer in the attached figure


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Answer:

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Step-by-step explanation:

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