Answer:
The number of
Small candles = x = 12 candles
Large candles = y = 16 candles
Step-by-step explanation:
You sell small and large candles at a craft fair. You collect $144 selling a total of 28 candles. How many of each type of candle did you sell? A photo shows a small candle labeled 4 dollars each and a large candle labeled 6 dollars each.
Let the number of
Small candles = x
Large candles = y
Our system of equations is:
x + y = 28 .......... Equation 1
x = 28 - y
A photo shows a small candle labeled 4 dollars each and a large candle labeled 6 dollars each.
4x + 6y = 144......... Equation 2
Substitute 28 - y for x in Equation 2
4(28 - y) + 6y = 144
112 - 4y + 6y = 144
- 4y + 6y = 144 - 112
2y = 32
y = 32/2
y = 16 candles
x = 28 - y
x = 28 - 16
x = 12 candles
Therefore:
The number of
Small candles = x = 12 candles
Large candles = y = 16 candles
They all ready did half the equation for u so all u have to do is 240 times 8= 1920 cubed inches
A number where the digit 3 has a value ten times greater than the 3 in 145,317 can be 143,417.
<h3>
How to work with place values?</h3>
In any number, the place value refers to the "place" that a digit has on a number. The first one is the units place, the second is the tens place, and so on.
As more in the left is the place value, the largest value it represents.
Particularly, in 145,317
The 3 is on the third place, so it represents the value 300.
For example, in 143,417
The 3 is more in the left than before, this time on the fourth place, this time the value of the 3 is 3,000.
Then, a number where the digit 3 has a value ten times greater than the 3 in 145,317 can be 143,417.
If you want to learn more about place values:
brainly.com/question/12386995
#SPJ1
10% = 10g/100ml. Ergo, 15ml/100ml (10g) = 1500mg of KCL
.9% NACL = 9g/1000mL, Ergo = 9000mg NaCl
Now we have to figure out how many mEqs of each salt we have.
MW of NaCl = 58.5
MW of KCl = 74.5
So, in moles, we have:
1500 KCl / 74.5 = 20.13 mmol KCl
9000 NaCl / 58.5 = 153.85mmol NaCl
Because the valence of both ions is one, as an example, it would be both 20.13 mEq of Cl- and K+ from 20.13 mmoles of KCL.
So, just add the two together, 20.13 + 153.85 = 174-ish.
5 times the Sum of 3 and 4, then subtract 4
