Question

Find an equation of the line that satisfies the given conditions. Through (−3, −6), perpendicular to the line 2x + 5y + 8 = 0

Answer 1

Answer:

Step-by-step explanation:

Using the point slope equation of a line to solve the question

y-y0=m(x-x0) where (x0,y0) is the point and m is the slope of the unknown line perpendicular to the given line.

Rewriting the equation given in the form y = MX+c

2x+5y+8 = 0

5y = -8-2x

y = -8/5-2x/5

From the equation, m = -2/5

Since the unknown line is perpendicular to the give line, the slope of the given line will be;

M = -1/(-2/5)

M = 5/2

Substituting the point and the slope into the equation above

y-(-6) = 5/2(x-(-3))

y+6 = 5/2(x+3)

y+6 = 5x/2+15/2

2y+12 = 5x+15

2y-5x = 15-12

2y-5x = 3 gives the required equation of the line