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OleMash [197]
3 years ago
9

2/3[8(5-2)^2 +3*2] How do I distribute the 2/3? And then solve the rest!

Mathematics
1 answer:
jolli1 [7]3 years ago
8 0

To distribute the 2/3, this is what you do.

2/3[8(5-2)^2 + 3*2] = (2/3)(8)(5-2)^2 + (2/3)(3*2) =

Now you can continue. You need to follow the correct order of operations.

= (2/3)(8)(3^2) + (2/3)(6)

= (2/3)(8)(9) + 4

= (2/3)(9)(8) + 4

= (6)(8) + 4

= 48 + 4

= 52

This is how I would have done it.

2/3[8(5-2)^2 + 3*2] =

= 2/3[8(3)^2 + 6]

= 2/3[8 * 9 + 6]

= 2/3[72 + 6]

= 2/3[78]

= 2 * 1/3(78)

= 2 * 26

= 52

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pi x diameter

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5 0
3 years ago
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I need help please.....
maria [59]
Here, Function: h(t)= -16t² + 70t + 40

So, put the value of t, (time at which you want to calculate the height)

h(1) = -16(1)² + 70(1) + 40
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Now, h(2) = -16(2)² + 70(2) + 40
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h(3) = -16(3)² + 70(3) + 40
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In short, Your height depends on time, and at each time it would be different, can be expressed by the coordinates on a Graph: (1, 94) (2, 116) (3, 106)

Hope this helps!


8 0
4 years ago
4/5+ 1/3 how much is it
Andreas93 [3]
4/5 = 12/15
1/3 = 5/15
17/15 = 1 2/15
4 0
3 years ago
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