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3 years ago

2/3[8(5-2)^2 +3*2] How do I distribute the 2/3? And then solve the rest!

Mathematics

1 answer:

jolli1 [7]3 years ago

8 0

To distribute the 2/3, this is what you do.

2/3[8(5-2)^2 + 3*2] = (2/3)(8)(5-2)^2 + (2/3)(3*2) =

Now you can continue. You need to follow the correct order of operations.

= (2/3)(8)(3^2) + (2/3)(6)

= (2/3)(8)(9) + 4

= (2/3)(9)(8) + 4

= (6)(8) + 4

= 48 + 4

= 52

This is how I would have done it.

2/3[8(5-2)^2 + 3*2] =

= 2/3[8(3)^2 + 6]

= 2/3[8 * 9 + 6]

= 2/3[72 + 6]

= 2/3[78]

= 2 * 1/3(78)

= 2 * 26

= 52

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Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

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