Question

Solve the following equation algebraically: Negative 16 = 16 x squared How many solutions does this equation have? Explain. a. Negative 1 = x squared; One solution because only -1 will satisfy the equation. b. Negative 1 = x squared; No real solution because there is no real number that, when squared, produces -1. c. 1 = x squared; Two solutions because the square root of 1 is positive 1 and negative 1. d. 1 = negative x squared; One solution because only -1 will satisfy the equation.

Answer 1

Answer:

The correct answer is b.

Step-by-step explanation:

$16 {x}^{2} = - 16$

${x}^{2} = - 1$

No real solutions.