Solve the following equation algebraically: Negative 16 = 16 x squared How many solutions does this equation have? Explain. a. N
egative 1 = x squared; One solution because only -1 will satisfy the equation. b. Negative 1 = x squared; No real solution because there is no real number that, when squared, produces -1. c. 1 = x squared; Two solutions because the square root of 1 is positive 1 and negative 1. d. 1 = negative x squared; One solution because only -1 will satisfy the equation.
No. Let's say we use 10 and 0.38. 1 X 10 is 10, so if anything is lower than 1, it will be lower than 10. Therefore, 0.38 X 10 is 3.8. This is less than the whole number, 10. Hope this is clear enough.
