9514 1404 393
Answer:
30°, 150°
Step-by-step explanation:
You know the answer to this because you have memorized the short table of trig function values.
sin(θ) = 1/2 for θ = 30° and θ = 150°
Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
• 4w -6 = -2
+6 +6
4w= 4
— —
4 4
w=1
• 4w - 6 = 2
+6 +6
4w =8
— —
4 4
w=2
It's a trick question. 1/2 is more than 2/8/
Simple...
you have: x-3y=18
You want to convert it into slope-intercept form or y=mx+b form-->>>
x-3y=18
Isolate the variable-->>
x-3y=18
-x -x
-3y=-x+18
Now simply divide...
y=
Thus, your answer.