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a_sh-v [17]
4 years ago
9

Can someone please help?

Mathematics
1 answer:
kifflom [539]4 years ago
5 0
Standard form means, move the variables to the left-hand-side and leave the constant all by herself on the right-hand-side, usually sorting the variables, so"x" goes first.

now, there's a denominator, we can do away with it, by simply multiplying both sides by the denominator, so let's do so,

\bf y=-\cfrac{2}{3}x+7\implies \boxed{3}\cdot y=\boxed{3}\cdot \left( -\cfrac{2}{3}x+7 \right)\implies 3y=-2x+21
\\\\\\
\stackrel{standard~form}{2x+3y=21}
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So we first minus 6 both sides
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hmm (this should be painfully obvous, but if not, here are steps)

7x^2-14x=-6
A(x^2-2x)=-6

7x^2-14x=-6=A(x^2-2x)
7x^2-14x=A(x^2-2x)
undistribute 7
7(x^2-2x)=A(x^2-2x)
divide both sides by (x^2-2x)
7=A

A=7
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