Answer:
Her grocery bill was <u>$4.62</u>.
Step-by-step explanation:
There is some mistake in question so the correct question is:
Sherry bought 6 apples at 43¢ per apple. She then bought 4 oranges at 51¢ per orange. How much was her grocery bill?
Now, to find the grocery bill.
As the units are given:
<em>43¢ per apple and </em>
<em>51¢ per orange.</em>
$1 = 100¢.
So, the cost of 6 apples = 
Thus, the cost of 6 apples = $2.58
And the cost of 4 oranges = 
Thus the cost of 4 oranges = $2.04
Now, to get the total grocery bill we add the cost of apples and oranges:
Therefore, her grocery bill was $4.62.
-----------------------------------------------
Information Given:
-----------------------------------------------
ON = 7x - 9
LM = 6x + 4
MN = x - 7
OL = 2y - 7
-----------------------------------------------
Since it is a parallelogram:
-----------------------------------------------
ON = LM and
MN = OL
-----------------------------------------------
ON = LM:
-----------------------------------------------
7x - 9 = 6x + 4
-----------------------------------------------
Subtract 6x from both sides:
-----------------------------------------------
x - 9 = 4
-----------------------------------------------
Add 9 to both sides:
-----------------------------------------------
x = 13
-----------------------------------------------
MN = OL:
-----------------------------------------------
x - 7 = 2y - 7
-----------------------------------------------
Sub x = 13:
-----------------------------------------------
13 - 7 = 2y - 7
-----------------------------------------------
Simplify:
-----------------------------------------------
6 = 2y - 7
-----------------------------------------------
Add 7 on both sides:
-----------------------------------------------
13 = 2y
-----------------------------------------------
Divide by 2:
-----------------------------------------------
y = 13/2
-----------------------------------------------
Answer: x = 13, y = 13/2 (Answer D)
-----------------------------------------------
<h3>Answer is -9</h3>
=================================
Work Shown:
(g°h)(x) is the same as g(h(x))
So, (g°h)(0) = g(h(0))
Effectively h(x) is the input to g(x). Let's first find h(0)
h(x) = x^2+3
h(0) = 0^2+3
h(0) = 3
So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.
Now let's find g(3)
g(x) = -3x
g(3) = -3*3
g(3) = -9
-------
alternatively, you can plug h(x) algebraically into the g(x) function
g(x) = -3x
g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)
g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3
g( h(x) ) = -3x^2 - 9
Next we can plug in x = 0
g( h(0) ) = -3(0)^2 - 9
g( h(0) ) = -9
we get the same result.
-- The trains start moving at the same time.
-- The space between them is initially 252.5 miles.
-- They reduce the distance between them at the rate of (124.7+253.5)=378.2mph.
-- It will take them (252.5 / 378.2) = 0.6676 hour to meet.
That's 40min 3.49sec .
-- After tooting and puffing toward each other for 8 minutes, they still have <em>32min 3.49sec</em> to go before they meet each other. We're all hoping that they're on different tracks.
33-23=10. 10+23=33. 23-10=13
the numbers are 23 and 10
