Question

PLS HELP!!!

Answer 1

Answer:

$P=\frac{11}{40}+\frac{1}{4}-\frac{1}{20}$

Step-by-step explanation:

Given,

Students of,

Consumer education, n(C) = 22,

French, n(F) = 20,

Both, n(C∩F) = 4,

Total students, n(S) = 80

Thus, the number of students from Consumer Education, French, or both,

n(C∪F) = n(C) + n(F) - n(C∩F)

= 22 + 20 - 4

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

Hence, probability of a student from Consumer Education, French, or both,

$P=\frac{n(C\cup F)}{n(S)}$

$=\frac{22+20-4}{80}$

$=\frac{22}{80}+\frac{20}{80}-\frac{4}{80}$

$=\frac{11}{40}+\frac{1}{4}-\frac{1}{20}$

LAST option is correct.

Answer 2

Answer:

The answer you chose is correct

Step-by-step explanation: