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zlopas [31]
3 years ago
7

Really Need Help Quick Please! Must turn this in . Please show work. Brainliest answer will be awarded to quickest, correct answ

er, with shown work.
A slide 4.1 meters long is makes an angle 35 degrees with the ground. To the nearest of a meter, how far above the ground is the top of the slide?

Mathematics
1 answer:
Anestetic [448]3 years ago
5 0
X = slide height
sine (35) = opp / hypotenuse
sine (35) = x / 4.1

x = 0.57358 * 4.1
x = <span> <span> <span> 2.351678 </span> </span> </span> meters
Okay to the nearest meter it is 2




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The 4th and 8th term of a G.P. are 24 and 8/27 respectively. find the 1st term and common ratio
beks73 [17]

Answer:

see explanation

Step-by-step explanation:

The n th term of a geometric progression is

• a_{n} = a₁ r^{n-1}

where a₁ is the first term and r the common ratio

given a₄ = 24, then

a₁r^{3} = 24 → (1)

Given a₈ = \frac{8}{27}, then

a₁r^{7} = \frac{8}{27} → (2)

Divide (2) by (1)

r^{4} = \frac{\frac{8}{27} }{24} = \frac{1}{81}

Hence r = \sqrt[4]{\frac{1}{81} } = \frac{1}{3}

Substitute this value into (1)

a₁ × (\frac{1}{3} )³ = 24

a₁ × \frac{1}{27} = 24, hence

a₁ = 24 × 27 = 648

4 0
3 years ago
What is the vertex of the quadratic function f(x)=x2+6x+16? Write your answer
Olenka [21]

Answer:

The vertex of the quadratic function is:

(x_{v}, y_{v})=\left(-3,\:7\right)

Step-by-step explanation:

Given the function

f\left(x\right)=x^2+6x+16

As the vertex of the form y=ax^2+bx+c is defined as:

x_v=-\frac{b}{2a}

As the quadratic function of parabola params are

a=1,\:b=6,\:c=16

so

x_v=-\frac{b}{2a}

x_v=-\frac{6}{2\cdot \:1}

x_v=-3

Putting x_v=-3 to determine y_v

y_v=\left(-3\right)^2+6\left(-3\right)+16

y_v=3^2-18+16

y_v=9-2

y_v=7

Therefore, the vertex of the quadratic function is:

(x_{v}, y_{v})=\left(-3,\:7\right)

5 0
3 years ago
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