Y > 3x +2<br><br>I'm having problems solving Inequalities.<br>Can someone help me????

Two airplanes are flying to the same airport. Their positions are shown in the graph. Write a system of linear equations that re

wariber [46]

Answer:

Airplane #1 equation: y=5/13x+42/13

Airplane #2 equation: y=1/3x+14

Step-by-step explanation:

So to find the slope of each airplane, you use the formula y2-y1/x2-x1. That means, for airplane#1 the equation will be 9-4/15-2. Simplify this and get 5/13. Then, for airplane#2, the equation will be 12-9/6-15. Simplify this and get 3/-9 and divide each side by 3 to get 1/-3 or -1/3. Next, use point slope formula to find the system of linear equations. Point slope formula is y-y1=m(x-x1). M is the slope. Use any point from the line. In this case, I will use (2,4). Tat means the first airplane's equation would be y-4=5/13(x-2). Then y-4=5/13x-10/13. Then, convert four into a fraction with a denominator of 13. This means, you have to multiply 4 by 13 to get 52/13. Add 52/13 to -10/13 to get 42/13. That means the first equation will be y=5/13x+42/13. The second equation point will be (6,12). This means the equation will be y-12=-1/3(x-6). Simplify this to get y-12=-1/3x+2. Simplify this to get y=1/3x+14. Therefore, Airplane#1 equation will be y=5/13x+42/13 and airplane #2 equation will be y=1/3x+14.

Hope this helps

6 0

3 years ago

Solve your equations below and right the algebraic steps, n/12 = 10

sdas [7]

$\frac{n}{12}=10$

Multiply both sides of the equation by 12

$\frac{n}{12}\times12=10\times12$ $n=\text{ 120}$

7 0

1 year ago

Mario has a business selling muffins. Let x be the price of a muffin. Then, the profit P for Mario’s business is given by p(x)=-

Rufina [12.5K]

To make a positive profit p(x)>0 we need to make:
$-100 x^{2} +350x-150 \ \textgreater \ 0$

Now we solve this for x:
$-2 x^{2} +7x-3 \ \textgreater \ 0$

We have:
a = -2
b = 7
c = -3

We will use formula for quadratic equation:
$x_{1} = \frac{-b+ \sqrt{ b^{2}-4ac } }{2a} \\ \\ x_{2} = \frac{-b- \sqrt{ b^{2}-4ac } }{2a} \\ \\ x_{1} = \frac{-7+ \sqrt{ 49-24 } }{-4} = \frac{-7+5 }{-4} = \frac{-2 }{-4} = \frac{1}{2} \\ \\ x_{2} = \frac{-7- \sqrt{ 49-24 } }{-4} = \frac{-7-5 }{-4} = \frac{-12 }{-4} = 3$

We got two solutions. One is fraction other is whole number. We will not consider fraction because the amount of muffins sold must be whole number. So our solution is:
x>3

5 0

3 years ago

Read 2 more answers

Student scored in the 83rd

melamori03 [73]

Answer:b

Step-by-step explanation:

5 0

2 years ago

there are 120 students in a school marching band. they march in an array with the same number of students in each row. what are

Sloan [31]

Answer:

20 X 6

Step-by-step explanation:

20 X 6 = 120 I'm not smart but this is pretty easy

5 0

2 years ago

Y > 3x +2I'm having problems solving Inequalities.Can someone help me????