Answer: V = (12in - 2*x)*(8 in - 2*x)*x
Step-by-step explanation:
So we have a rectangular cardboard sheet, and we cut four squares of side length x in each corner so we can make a box.
Remember that for a box of length L, width W and height H, the volume is:
V = L*W*H
In this case, the length initially is 12 inches, but we remove (from each end) x inches of the length, then the length of the box will be:
L = 12 in - 2*x
For the width we have a similar case:
W = 8in - 2*x
And te height of the box will be equal to x, then:
H = x
This means that the volume is:
V = (12in - 2*x)*(8 in - 2*x)*x
Here we can see the connection between the cutout and the volume of the box
To find this I would use the pythagorean theorem which is:
a^2 + b^2 = c^2
Since we already know c = hypotenuse, and a side of the shorter sides we can plug them it like this:
11^2 + b^2 = 12^2
121 + b^2 = 144
b^2 = 23
√23 = 4.79
Round:
B. 4.8 would be your answer!
Answer:
15.1
Step-by-step explanation:
29.34
-14.24
---------
15.10
Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with 
Expected number before 1 defective(n = 1). So

Variance is:

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
the base is 5unit and the height is 9unit