23/40 can't be simplified as it has no common factors
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Answer:
$519
Step-by-step explanation:
Given the amount of profit made expressed as y=-2x^2+105x-859
At maximum profit, dy/dx = 0
dy/dx = -4x + 105
0 = -4x + 105
4x = 105
x = 105/4
x = 26.25
Substitute into the original function
y=-2x^2+105x-859
y=-2(26.25)^2+105(26.25)-859
y = - 1,378.125+2,756.25-859
y = 519.125
Hence the maximum amount of profit the company can make is $519
Answer:
The worth of the car after 6 years is £2,134.82
Step-by-step explanation:
The amount at which Dan buys the car, PV = £2200
The rate at which the car depreciates, r = -0.5%
The car's worth, 'FV', in 6 years is given as follows;

Where;
r = The depreciation rate (negative) = -0.5%
FV = The future value of the asset
PV = The present value pf the asset = £2200
n = The number of years (depreciating) = 6
By plugging in the values, we get;

The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))
The correct answers is 0.66 or .66