Answer:
x = 6 cos t
y = 6 sin t
where t varies from 0 to 2pi
Step-by-step explanation:
Given that an ellipse is centred at the origin in xy plane.
So equation would be of the form
Major axis =2a= 12
so a=6
Minor diameter = 8
b = 8/2 = 4
a=6 and b =4
Also (6,0) should correspond to t=0
So best parametrization would be
x = 6 cos t
y = 6 sin t
where t varies from 0 to 2pi
Answer:
the coefficient of x is 2
Step-by-step explanation:
(3x - y + z) + (2x - y - z) - (3x - y - z) = 3x - y + z + 2x - y - z - (3x - y - z)
Apply the distributive law: - (a - b) = -a + b
Therefore, - (3x - y - z) = -3x + y + z
So (3x - y + z) + (2x - y - z) - (3x - y - z) = 3x - y + z + 2x - y - z - 3x + y + z
Collect like terms: = 3x + 2x - 3x - y - y + y + z - z + z
Combine like terms: = 2x - y + z
Therefore, the coefficient of x is 2
Therefore, the coefficient of x is 2
Answer:
26.39
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
The hypotenuse squared is equal to the sum of the legs squared in a right triangle.
∴ c² = a² + b² (Pythagorean’s Theorem)
c² = 3.4² + 6.7² (substitute the given values for a & b)
c² = 11.56 + 44.89 (square both right hand terms)
c² = 56.45 (add the right hand side values)
c = √56.45 (square root of both sides)
c ≈ 7.5 to the nearest tenth QED
Answer:
-11.8
Step-by-step explanation:
hope this helps!!!:)
