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Arada [10]
3 years ago
9

Suppose that for you to make the golf team you need to score no more than 74 on average over 5 games. If you scored 77,71,77, an

d 67 in your first 4 games. What is the highest score you can shoot in your 5th game and still make the team?
Mathematics
2 answers:
fomenos3 years ago
8 0
(77 + 71 + 77 + 67 + x) / 5 < 74
(292 + x) / 5 < 74
292 + x < 74 * 5
292 + x < 370
x < 370 - 292
x < 78...the highest score u can shoot is 77 
Pie3 years ago
3 0

Answer:

The highest score we can shoot in our 5th game and still make the team is:

         78

Step-by-step explanation:

We scored 77,71,77, and 67 in our first 4 games.

Let score in fifth game be x

If we want a average score of no more than 74 over 5 games,then

    \dfrac{71+77+77+67+x}{5}\leq 74

       \dfrac{292+x}{5}\leq 74

                292+x≤370

                      x≤370-292

                     x≤78

Hence, the highest score we can shoot in our 5th game and still make the team is:

         78

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8 0
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Answer:

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5 0
3 years ago
Please help me out? thank you.
anzhelika [568]
It’s the fourth answer
4 0
2 years ago
13 copies of the small rectangle shown below have been used to make the larger rectangle.
Nikolay [14]

Answer:

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I hope it helps you!

8 0
2 years ago
∠ABD is formed by a tangent and a secant intersecting outside of a circle. If minor arc AC = 78° and minor arc CD = 124°, what i
lana [24]
Minor arc AD is 360° -124° -78° = 158°. Then angle ABD is
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The appropriate selection is
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4 0
2 years ago
Read 2 more answers
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