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2 years ago

Is this correct?(top answerers)

Mathematics

2 answers:

Y_Kistochka [10]2 years ago

7 0

Answer:

Step-by-step explanation:

Again, I'm not totally sure I know what your choices are or if you can do what I would propose.

y = 2

-x^2

+ 5

Is the order that I would put them in. What get's to me is how much is included in a step, but I have given you the correct order.

valina [46]2 years ago

3 0

Answer:

y = x + 5, y = 2^x, y = -x, y = x^2

Step-by-step explanation:

$y=2^{-x^2}+5\\\\f(x)=x+5\\\\g(x)=2^x\\\\h(x)=-x\\\\i(x)=x^2\\\\f\Bigg(g\bigg(h(i(x))\bigg)\Bigg)\\\\h(i(x))=-x^2\\\\g\bigg(h(i(x))\bigg)=2^{-x^2}\\\\f\Bigg(g\bigg(h(i(x))\bigg)\Bigg)=2^{-x^2}+5$

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Please help, anything would be very much appreciated

jasenka [17]

Answer:

answer is 5.50

Step-by-step explanation:

multiply 2.75 times two because 3 by 5 is half of 9 by 15

7 0

2 years ago

Read 2 more answers

Prove the following

fomenos

Answer:

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

<h2 /><h2><u>Consider</u></h2>

$\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \dfrac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \}cos(23π+x)cos(2π+x)$

$\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) = sinx$

$\rm \: {cos \: (2\pi + x) }$

$\rm \: \cot \bigg( \dfrac{3\pi}{2} - x \bigg) \: = \: tanx$

$\rm \: cot(2\pi + x) \: = \: cotx$

So, on substituting all these values, we get

$\rm \: = \: sinx \: cosx \: (tanx \: + \: cotx)$

$\rm \: = \: sinx \: cosx \: \bigg(\dfrac{sinx}{cosx} + \dfrac{cosx}{sinx}$

$\rm \: = \: sinx \: cosx \: \bigg(\dfrac{ {sin}^{2}x + {cos}^{2}x}{cosx \: sinx}$

$\rm \: = \: 1=1$

<h2>Hence,</h2>

$\boxed{\tt{ \cos \bigg( \frac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \frac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \} = 1}}$

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<h2>ADDITIONAL INFORMATION :-</h2>

Sign of Trigonometric ratios in Quadrants

sin (90°-θ) = cos θ
cos (90°-θ) = sin θ
tan (90°-θ) = cot θ
csc (90°-θ) = sec θ
sec (90°-θ) = csc θ
cot (90°-θ) = tan θ
sin (90°+θ) = cos θ
cos (90°+θ) = -sin θ
tan (90°+θ) = -cot θ
csc (90°+θ) = sec θ
sec (90°+θ) = -csc θ
cot (90°+θ) = -tan θ
sin (180°-θ) = sin θ
cos (180°-θ) = -cos θ
tan (180°-θ) = -tan θ
csc (180°-θ) = csc θ
sec (180°-θ) = -sec θ
cot (180°-θ) = -cot θ
sin (180°+θ) = -sin θ
cos (180°+θ) = -cos θ
tan (180°+θ) = tan θ
csc (180°+θ) = -csc θ
sec (180°+θ) = -sec θ
cot (180°+θ) = cot θ
sin (270°-θ) = -cos θ
cos (270°-θ) = -sin θ
tan (270°-θ) = cot θ
csc (270°-θ) = -sec θ
sec (270°-θ) = -csc θ
cot (270°-θ) = tan θ
sin (270°+θ) = -cos θ
cos (270°+θ) = sin θ
tan (270°+θ) = -cot θ
csc (270°+θ) = -sec θ
sec (270°+θ) = cos θ
cot (270°+θ) = -tan θ

7 0

2 years ago

Read 2 more answers

16.2 Jumping Rope

slava [35]

Answer:

Percentage of Diego's time is 75%.

Step-by-step explanation:

Given : Jumping Rope hool held a jump-roping contest. Diego jumped rope for 20 minutes. A school held a jur Jada jumped rope for 15 minutes.

To find : What percentage of Diego's time is that?

Solution :

Diego jumped rope for 20 minutes.

Jada jumped rope for 15 minutes.

Percentage of Diego's time is given by,

$\text{Percentage change}=\frac{\text{Jada time}}{\text{Diego time}}\times 100$

$\text{Percentage change}=\frac{15}{20}\times 100$

$\text{Percentage change}=75\%$

Therefore, percentage of Diego's time is 75%.

7 0

2 years ago

2) Find the slope of the line

algol13

Assuming each line goes up by 1. we basically need to find a number that goes by rise/run. to get to the next point we need to go up 1, then to the left by 3. notice the slope is negative so we need to add a negative integer.

answer:

-1/3 (C)

hope this helps! :D

4 0

3 years ago

Read 2 more answers

How to find the rate of change of the volume of cone?

sleet_krkn [62]

You can use calculus ( related rates). Given the rate os change of the radius for example you can find the rate of change of volume using differential calculus.

8 0

3 years ago