Answer:
<em>well non of the answer choices are exact but i would say a/the first one. im not sure but they should add up to about 7.65%.</em>
Step-by-step explanation:
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Answer:
Step-by-step explanation:
Your exponential formula is in the form y = ab^x. In this form, the coefficient 'a' is the initial value, the y-intercept, the value when x=0. The value 'b' is the growth factor, which is 1 more than the growth rate per increment of x. This problem is asking for the growth rate to be expressed as a percentage.
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Given p(x) = 78500(1.02^x), we can compare to the exponential function form to see that ...
- a = 78,500
- b = 1.02 = 1 +0.02 = 1 +2%
The value of x is zero in the year 2000, so the population that year is ...
p(0) = a = 78,500
The increase per year is the value of 'b' with 1 subtracted:
growth rate = 2% per year
The formula is
A=p (1+r/k)^kt
A fund needed 30000
p Amount invested?
R interest rate 0.1
K compounded semiannual 2
T time 1 year
Solve the formula for p to get
P=A÷(1+r/k)^kt
P=30,000÷(1+0.1÷2)^(2×1)
P=27,210.88
Y = x - 2. Then graph the equation and verify your answers.
Answer:
$6,250
Step-by-step explanation:
5% of 5000 = .05 x 5000 = 250 this finds the amount gained per year
250 x 5 = 1,250 this is the amount earned over 5 years
5000 + 1250 = 6,250 this is the total after 5 years.
Hope this helps!
