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ololo11 [35]
3 years ago
5

your coach assigned 15 practice exercises. You completed 6 exercises last week and 3 exercises this week. What fraction of the 1

5 exercises did you complete?
Mathematics
2 answers:
Lorico [155]3 years ago
8 0
You completed 9/15 of the exercises! :D
weqwewe [10]3 years ago
4 0
Total of 15 practice exercises.....u completed 6 last week and then 3 this week...so u completed (6 + 3) = 9 out of 15 exercises...

9/15 which reduces to 3/5 <== what u have completed
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can you assume that any fraction is in simplest form if either the numerator or denominator is a prime number?
vesna_86 [32]

Answer:

some occasions yes and other no for example if a fraction was 3/9 the numerator is prime but the fraction can still be simplified to 1/3 but a number were 3/5 then you wouldn't be able to simplify it


4 0
3 years ago
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Solve (MAFS.912.A-REI.2.3)
Vikki [24]

Answer:

c,=2d=-2

Step-by-step explanation:

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2 years ago
Bethany is baking cookies for her school's bake sale. She plans to bake more than 185 cookies, in batchs or 12 cookies. so far,
Aleks [24]

Answer:

48+12b≥185

Step-by-step explanation:

Inequality: 48+12b≥185

Why? she has already backed 48 cookies so you just need to find how many more she needs to bake. (she doesn't need 185 cookies anymore since she's already baked 48)

You don' t need to solve the question,  

But here is how you do...

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5 0
3 years ago
Given g(x) = 2x + 5, find g(1)
saul85 [17]

Answer:

g(1) =7

Step-by-step explanation:

g(x) = 2x + 5

Let x=1

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4 0
3 years ago
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100 points for correct answer
Tems11 [23]

Answer:

\dfrac{x}{3}+\dfrac{3}{y}

Step-by-step explanation:

<u>Given fraction</u>:

\dfrac{xy+9}{3y}

\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:

\implies \dfrac{xy}{3y}+\dfrac{9}{3y}

Rewrite 9 as 3 · 3:

\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}

\implies \dfrac{x}{3}+\dfrac{3}{y}

7 0
9 months ago
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