To find the gradient of a line you use this equation: Rise / Run
I am assuming this is a graph where both the x and y-axis increase in value by one.
So first of all, you should draw out this graph.
Second, draw a point at each of the given coordinates.
Now, join these points by drawing a right angle triangle. Put simply, draw a line from the point (4, -7) down until it is on the same level as the point (2, -3), then draw a line across.
Finally, measure the length of both these sides and use them in the equation above.
Let's assume the rise (vertical line) and the run (horizontal line) are 5 and 8 respectively. We can do 5/8 to get a gradient which is 0.625.
Answer:
A. 264
Step-by-step explanation:
First, we have to find the value of x. Then we can use that to find the required arc measure.
∠M = (1/2)(arc KN - arc LN)
60 = (1/2)((18x -6) -(5x +17)) = (1/2)(13x -23) . . . . substitute and simplify
120 = 13x -23 . . . . . . . multiply by 2
143 = 13x . . . . . . . . . . add 23
11 = x . . . . . . . . . . . . . . divide by 13
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arc KNL = (arc KN) + (arc NL) = (18x -6) +(5x +17) = 23x +11
= 23·11 +11
arc KNL = 264 . . . . degrees
You got this!!!! just don’t rush, if you really don’t know the answer, just chose letter C hahah :)
Answer:
Step-by-step explanation:
The tangent equation = side opposite angle / side beside angle
which in this case is 
which is the third choice
Hope that helps!
Answer:
6
(assuming the units is in centimetres)
Step-by-step explanation:
Hi, hope this helps!
Method 1:
Calculate this shape as a trapezium. This is a trapezium because it has one pair of parallel sides. The way to calculate the area of a trapezium is this:
- Half the sum of the parallel sides
- Multiply the perpendicular height between them
In this case, 4 and 2 are parallel, so we add them together (4 + 2 = 6) then we divide by two (6 ÷ 2 = 3). Then we multiply our answer by the perpendicular length between the two parallel sides (assuming the side on the left is at a right-angle, 3 x 2 = 6).
Method 2:
Calculate this shape as a rectangle + a triangle. If you split the shape so the pointy bit on the right becomes a triangle and the left becomes a square, you can calculate the area without knowing the formula for calculating a trapezium (see above ^).
- Area of the square / rectangle = length x width = 2 x 2 = 4
- Area of the triangle = 1/2 x length x width = 2 x 2 x 1/2 = 4 x 1/2 = 4 ÷ 2 = 2
Then we add the two areas together (4 + 2 = 6).
I hope this helped and I wasn't waffling on :)
Bluey