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Alex Ar [27]
4 years ago
6

janie served 4 same zise pizzas at the class party. explain how to find how many slices of pizza janie served if the angle for e

ach slice turns though a right angle
Mathematics
1 answer:
guapka [62]4 years ago
8 0
If each slice turns a right angle that means it turns 90* so you can only have two turns per pizza which gives 4 slices (90+90+90+90=360 - this is how many degrees in a circle) so per pizza 4 slices. For four pizzas that is 4x4 which is 16 so 16slices
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3 years ago
3. The Leakey Shipping Company uses small containers with a volume of 2.5 m3and large containers with a volume of 4 m3. A shipme
Serga [27]

Given:

• Volume of small containers = 2.5 m³

,

• Volume of large containers = 4 m³

,

• Number of containers in the shipment = 140

,

• Total volume = 440 m³

Let's find the number of the size of each container used.

Let s represent the number of small containers

Let L represent the number of large containers.

• Equation for number of containers:

s + L = 140

• Equation for total volume:

2.5s + 4L = 140

Hence, we have the set of equations:

s + L = 140...........................equation 1

2.5s + 4L = 440...................equation 2

Let's solve the set of equations simultaneously using substitution methos.

Rewrite equation 1 for L:

L = 140 - s...........................equation 3

Substitute (140 -s) for L in equation 2:

2.5s + 4(140 - s) = 440

Apply distributive property:

2.5s + 4(140) + 4(-s) = 440

2.5s + 560 - 4s = 440

Combine like terms:

2.5s - 4s + 560 = 440

-1.5s + 560 = 440

Subtract 560 from both sides:

-1.5s + 560 - 560 = 440 - 560

-1.5s = -120

Divide both sides by -1.5:

\begin{gathered} \frac{-1.5s}{-1.5}=\frac{-120}{-1.5} \\  \\ s=80 \end{gathered}

Substitute 80 for s in either of the equations.

Take equation 3.

L = 140 - s

L = 140 - 80

L = 60.

Therefore, we have the solutions:

s = 80 and L = 60

Therefore, the company used 80 small containers and 60 large containers

5 0
1 year ago
What is 2<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="\frac{1}{5}" align="
vivado [14]

2\dfrac{1}{5}+1\dfrac{1}{10}=2+\dfrac{1}{5}+1+\dfrac{1}{10}=(2+1)+\left(\dfrac{1}{5}+\dfrac{1}{10}\right)\\\\=3+\left(\dfrac{1\cdot2}{5\cdot2}+\dfrac{1}{10}\right)=3+\left(\dfrac{2}{10}+\dfrac{1}{10}\right)=3+\dfrac{2+1}{10}=\boxed{3\dfrac{3}{10}}

7 0
3 years ago
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