Answer:
1 hour would be 10 $ each
Step-by-step explanation:
1)$10
2)$50
3)$80
I hope this helps
Answer:
150 x - 80 y + 50 - 50 x - 25 y + 20
<em><u>Arranging </u></em><em><u>like </u></em><em><u>terms </u></em>
150 x - 50 x -25 y - 80y + 50 + 20
100x - 105 y + 70
<h3>5 ( 20x - 21y + 14) </h3>
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)