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Juli2301 [7.4K]
2 years ago
12

what is another way to write 297.3. Fill in: 2hundreds, 9tens, 5 ones + __________tenths I tried 2.3, but was told that was inco

rrect. Please help. Thank you!
Mathematics
1 answer:
Schach [20]2 years ago
7 0
Maybe it is 23 tenths ???
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List the two factor pairs of 10
Triss [41]
The factors of 10 are 1, 2, 5, and 10. You can also look at this the other way around: if you can multiply two whole numbers to create a third number, those two numbers are factors of the third. 2 x 5 = 10, so 2 and 5 are factors of 10. 1 x 10 = 10, so 1 and 10 are also factors of 10.
3 0
2 years ago
What is the solution to the system of equations graphed below y=-2x+4 y=x-5
Tpy6a [65]

Answer:

D. (3, -2)

Step-by-step explanation:

The point where both lines meet is the solution to the system of equations.

3 0
3 years ago
Read 2 more answers
Suppose there is a 1.1 Fahrenheit a drop in temperature for every thousand feet that an airplane climbs into the sky and the tem
Mashutka [201]

Answer:

45.8 degrees

Step-by-step explanation:

We know that the temp before take off is 57.9

We also know the temp decreases every 1,000 feet so

if we are 11,000 feet in the air and divide that 11000/1000=11

We know that the temp drops 11 times

11x1.1=12.1

57.9-12.1=45.8 degrees

3 0
3 years ago
Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} 

2 =   e^{ \alpha t} 

 \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
Translate the sentence into an inequality.<br> The sum of 4 and y is less than 15.
bulgar [2K]
I believe the answer would be: 4+y<15
5 0
2 years ago
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