Answer:
The length of the mosquito in the picture is 117.6 mm.
Step-by-step explanation:
This question can be solved using a rule of three.
The real size of the mosquito is 16 mm, which is 100% = 1.
In the picture, the size is magnified 635%, so it is 100+635 = 735% = 7.35. So
16mm - 1
x mm - 7.35
x = 7.35*16 = 117.6
The length of the mosquito in the picture is 117.6 mm.
I believe that answer is c
Answer:

Step-by-step explanation:
Answer:
2.5 ft
Step-by-step explanation:
Answer:
- -108.26
- -108.13
- -108.052
- -108.026
- -108
Step-by-step explanation:
A graphing calculator or spreadsheet is useful for making the repeated function evaluations required.
The average velocity on the interval [a,b] will be ...
v avg = (y(b) - y(a))/(b-a)
Here, all the intervals start at a=3, so the average velocity for the given values of t will be ...
v avg = (y(3+t) -y(3))/((3+t) -3) = (y(3+t) -y(3))/t
This can be computed for each of the t-values given. The results are shown in the attached table.
__
We note that the fractional part of the velocity gets smaller in proportion to t getting smaller. We expect it to go to 0 when t goes to 0.
The estimated instantaneous velocity is -108 ft/s.
_____
We can simplify the average velocity equation to ...
v avg = ((48(3+t) -26(t+3)^2) -(48(t+3) -26(3)^2)) / t
= (48t -26(t^2 +6t))/t
= 48 -26t -156
<em> v avg = -108 -26t</em>
Then the average velocity at t=0 is -108.