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Viktor [21]
3 years ago
7

A train leaves boston at 2:00 pm. a second train leaves the same city in the same direction at 6:00 pm. the second train travels

48mph48⁢mph faster than the first. if the second train overtakes the first at 11:00 pm, what is the speed of each of the two trains?
Mathematics
1 answer:
AURORKA [14]3 years ago
3 0
\boxed {\boxed { \text {Distance = Speed x Time}}}

<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x 
Distance = Time x Speed = 9x

<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)

Since both the distance they traveled are the same, we equate the distance to solve for x.

<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60

<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph

Answer: The spend of the two trains are 60 mph and 108 mph.
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Answer:

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Step-by-step explanation:

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Let us denote that:

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Use the equations (i) and (ii) to determine the value of <em>x</em> as follows:

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