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3 years ago

10

In a survey of 2,100 people who owned a certain type of car, 630 said they would buy that type of car again. What percent of th

e people surveyed were satisfied with the car?

2 answers:

castortr0y [4]3 years ago

7 0

Answer:

30%

Step-by-step explanation:

____ [38]3 years ago

6 0

30 percent ok good.(:

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The table shows the hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale. Grade 7 Grade 8 20 21 15

Naddika [18.5K]

Answer:

1. The interquartile range for the grade 7 data is 6.

2. The interquartile range for the grade 8 data is 6.

3. The difference of the medians of the two data sets is 2.

4. The difference is about 1/3 times the interquartile range of either data set.

Step-by-step explanation:

The hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale is given by the following table.

Grade 7 Grade 8

20 21

15 29

30 14

24 19

18 24

21 25

The data set for grade 7 is

20, 15, 30, 24, 18, 21

Arrange the data in ascending order.

15, 18, 20, 21, 24, 30

Divide the data in four equal parts.

(15), 18, (20), (21), 24,( 30)

$Q_1=18, Median=\frac{20+21}{2}=20.5, Q_3=24$

The interquartile range for the grade 7 data is

$IQR=Q_3-Q_1=24-18=6$

Therefore the interquartile range for the grade 7 data is 6.

The data set for grade 8 is

21, 29, 14, 19, 24, 25

Arrange the data in ascending order.

14, 19, 21, 24, 25, 29

Divide the data in four equal parts.

(14), 19, (21), (24), 25, (29)

$Q_1=19, Median=\frac{21+24}{2}=22.5, Q_3=25$

The interquartile range for the grade 8 data is

$IQR=Q_3-Q_1=25-19=6$

Therefore the interquartile range for the grade 8 data is 6.

The difference of the medians of the two data sets is

$D=22.5-20.5=2$

Therefore the difference of the medians of the two data sets is 2.

Let the difference is about x times the interquartile range of either data set.

The IQR of each data is 6.

$D=x(IQR)$

$2=x(6)$

$\frac{2}{6}=x$

$\frac{1}{3}=x$

Therefore the difference is about 1/3 times the interquartile range of either data set.

8 0

3 years ago

Need help solving the equation, trying to figure whether I multiply or divide.

USPshnik [31]

Answer:

m∠B = 43°

b = 26.1

c = 38.3

Step-by-step explanation:

By applying triangle sum in the given triangle,

47° + 90° + m∠B = 180°

137° + m∠B = 180°

m∠B = 43°

By applying sine ratio to the angle measuring 47°.

sin(47°) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

= $\frac{28}{c}$

c = $\frac{28}{\text{sin}(47^{\circ})}$

c = 38.28

c ≈ 38.3

By applying cosine rule,

cos(47°) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

= $\frac{b}{c}$

= $\frac{b}{38.3}$

b = 38.3[cos(47°)]

b = 26.1

5 0

3 years ago

Pls help I’ll brainlest and add extra points do all of them

emmasim [6.3K]

Answer:

17/16= 1.06 (rounded)

16/17= 0.94 (rounded)

9/45= 0.2

5/13= 0.38 (rounded)

-28/35= -0.8

15/20= 0.75

Step-by-step explanation: Hope this helps

3 0

3 years ago

What is the end behavior of a sixth degree polynomial function whose leading coefficient is

bija089 [108]

Answer:

both ends tend toward negative infinity

Step-by-step explanation:

The ends of an even-degree polynomial go in the same direction. The sign of that direction matches the sign of the leading coefficient.

Here, the leading coefficient is negative, so ...

y → -∞ when x → ±∞

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3 years ago

HELP! I WILL GIVE BRAINLIEST AND RATING!

Ede4ka [16]

Answer:

The answer is C.

6 0

3 years ago

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