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saw5 [17]
4 years ago
9

I need help with these 2 problems

Mathematics
1 answer:
Molodets [167]4 years ago
6 0
The formula for the area of a rectangle is b\cdot h, so given that h=5x+3, b=3x-4, the area of the entire rectangle is (3x-4)(5x+3)=15x^2-20x+9x-12=15x^2-11x-12.. We now subtract the white part, with area 2x*4x=8x^2, so 15x^2-11x-12-8x^2=7x^2-11x-12
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isabel lives 3/4 mile from school, Janet lives 2/3 mile from school how much farther in miles does isabel live from school than
anyanavicka [17]
Hey There!

Steps to solve (steps will be in numerical order)

1. Find the lcd of the fractions \frac{3}{4} and <span>\frac{2}{3} . The lcd for both problems will be 12.

2. To rewrite </span>\frac{3}{4} you have to multiply the numerator and denominator by three since the lcd is 12. So you're new fraction will be \frac{9}{12}. For the second fraction, since the lcd is 12 you will multiply the numerator and denominator by 4. You're new fraction will be <span>\frac{8}{12}.

3. Since the problem contains the math keyword "Further", you automatically know you have to subtract, now subtract </span>\frac{9}{12} - <span>\frac{8}{12}. First, start of by subtracting the numerators, so subtract 9-8=1 , remember the denominators will always stay the same.

In conclusion, you're answer will be </span>\frac{1}{12}, so Isabel lives <span>\frac{1}{12} farther away from Janet.

Hope This Helps :)

</span>
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3 years ago
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