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SashulF [63]
3 years ago
14

Who's your favorite grey's anatomy character?

Mathematics
2 answers:
lesya692 [45]3 years ago
5 0
Sooo i didn’t like April at first but now i love her
katrin [286]3 years ago
5 0

Answer:

Mc Steamy

Step-by-step explanation:

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What is the answer to y=(2x+5)(x-2) in standard form
docker41 [41]

Answer:

i think it is Rewrite in Standard Form y=2x+5. y=2x+5 y = 2 x + 5.

Step-by-step explanation:

5 0
3 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
3 years ago
The lynch family bought a house for $75,300.a few year later, they sold the house for $80,250.how much greater was the selling p
Doss [256]
You take away from them so your answer will be 4,950



hope this help you with your question~~~~

love


meowlover

4 0
4 years ago
Rosa wants 2 pairs of jeans that cost $32 each .she has a coupon for $10 off the price of one pair .what price will rosa pay for
Phoenix [80]

Answer:

$54

Step-by-step explanation:

An expression for the total cost would be:

1($32) + ($32-$10) = $32 + $22 = $54

8 0
4 years ago
what is the equation of the line that passes through (-2,-3) and is perpendicular to 2x-3y=6? ...?
sergij07 [2.7K]
The equation given in the question is

2x - 3y = 6
Dividing both sides of the equation by 3, we get
2/3 x - y = 2
y = 2/3 x - 2
Then, from the above equation we can tell that the slope of the line in the graph is 2/3. The slope of a line perpendicular to this slope will be - 3/2. The line also contains the points (-2,-3). 
Then, the equation of the perpendicular line will be
y = mx + b
- 3 = (- 3/2)(- 2) + b
- 3 = 3 + b
b = - 6
Then
y = (-3/2)x - 6
y + 6 = (- 3/2)x
2y + 12 = - 3x
3x + 2y = - 12
4 0
3 years ago
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