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3 years ago

Find the solution to the inaquality N+35<22

Mathematics

2 answers:

NikAS [45]3 years ago

7 0

Step-by-step explanation:

$N + 35 < 22$

To find a solution to this inequality, we need to get $N$ to one side of the equation by itself. Since we have $N + 35$ on the left-hand side of the equation, we can get

$N + 35 < 22$

$N + 35 - 35 < 22 - 35$

$N < -13$

melamori03 [73]3 years ago

5 0

Answer:

To find a solution to this inequality, we need to get to one side of the equation by itself. Since we have on the left-hand side of the equation, we can get

explanation:

hope this helps

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3 years ago

45% of 40 is 18% of what number?

alexandr1967 [171]

So 45% OF 40 is
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18 is 18% of what number?
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Hope this helps

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3 years ago

In a random sample of 74 women at a company, the mean salary is $39,902 with a standard deviation of $3270 in a random sample of

ValentinkaMS [17]

The correct answer is the first choice, ($1818.30, $5077.70.)

To find this, we first find the z-score based on the confidence level:
Convert 95% to a decimal: 95%=95/100 = 0.95
Subtract from 1: 1-0.95 = 0.05
Divide by 2: 0.05/2 = 0.025
Subtract from 1: 1-0.025 = 0.975

Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 1.96.

Next, we identify
$\overline{x_1}=39902; \overline{x_2}=36454; n_1=74; n_2=40; \sigma_1=3270; \sigma_2=4677$

Next we find
$(\overline{x_1}-\overline{x_2})=(39902-36454) = 3448$

Next we find
$\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}
\\
\\=\sqrt{\frac{3270^2}{74}+\frac{4677^2}{40}}=\sqrt{\frac{10692900}{74}+\frac{21874329}{40}}
\\
\\=831.479$

Next, we multiply this value by z:
1.96(831.479) = 1629.70

The confidence interval is given by
$3448\pm1629.70
\\
\\=(3448-1629.70, 3448+1629.70)
\\
\\=(1818.30, 5077.70)$

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3 years ago