Answer:
11, 15, 26, 41, could be an answer
Try this:
1) note that weight of pure antifreeze before mixing and after mixing is the same. So, if 'x' is weight of pure antifreeze in 50% solution, it is possible to make up equation before mixing: 0.5x+0.2*90.
2) there are 0.2*90=18 gal. of pure antifreeze in the 20% solution. If 'x' gal. is the weight of pure antifreeze in 50% sol. and 18 gal. is the weight of pure antifreeze in 20% sol., it is possible to make up an equation after mixing: 0.4(x+18).
3) using the both parts: 0.5x+0.2*90=0.4(x+18) ⇒ x=54 gal. of <u>pure</u> weight.
4) to find 50% solution of 54 gal. pure weight just 54:0.5=108 gal.
Answer: 108 gal.
Answer:
$90
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 9%/100 = 0.09 per year,
then, solving our equation
I = 2000 × 0.09 × 0.5 = 90
I = $ 90.00
The simple interest accumulated
on a principal of $ 2,000.00
at a rate of 9% per year
for 0.5 years is $ 90.00.
The correct answer is Undefined
I just did this in pre-calculus and I’m positive it is correct
Answer:
median
Step-by-step explanation:
The centre of every data set is the second quartile/50th percentile/median
