What pattern of growth will a population with limited resources show? *

When corn plants are too tall, they lodge (topple over) prior to harvest. This is bad since the grain is often lost when it cann

Shalnov [3]

Answer:

The phenotypic variance= 2113

The eenvironmenal variance= 644

The genetic variance= 1469

The broad-sense heritability = 0.695

Explanation:

To determine the phenotypic variance, we need to know the calculate the environmental variance and the genetic variance first;

because Phenotypic variance = V(p) such that;

V(p) = V(e) + V(g)

where V(e) = environmental variance and V(g) = genetic variance

Therefore, Environmental variance can be defined as a portion of phenotypic variance due to differences in the environments to which the individuals in a population have been exposed. The total amount of variance observed is dependent on the genetic component, determined by the variation that is inherited.

This implies that V(e)= initial variance which was there in the parents ( i.e Variance of inbred line 1 = 311 and Variance of inbred line 2 = 333 )

V(e) = (311 + 333) = 644

Genetic Variance simply refer to the variance that occurs or preferrably , that is observed after inbreeding (i.e Variance of F1 = 316 and Variance of F2 = 1153)

V(g) = (316 + 1153) = 1469

Now, back to phenotypic variance = V(e) + V(g)

substituting the parameters we have; 1469 + 644 = 2113

Broad-sense heritability can be calculated as the ratio of total genetic variance to total phenotypic variance.

= V(g)/ V(p)

= 1469/ 2113

= 0.695

4 0

2 years ago

Which of these processes are chemical reactions? boiling an egg crushing spices vegetables rotting chopping vegetables dew formi

Tju [1.3M]

Boiling an egg and vegetables rotting.

7 0

3 years ago

Read 2 more answers

In a unique species of plants, flowers may be yellow, blue, red, or mauve. All colors may be true-breeding. If plants with blue

Zolol [24]

Answer:

F1) 100% bbRr, red flowered plants.

Explanation:

<u>Available data:</u>

flowers may be yellow, blue, red, or mauve
colors may be true-breeding
the cross of blue-flowered plants with red-flowered plants, produce plants that have yellow flowers
F2 generation: 9/16 yellow, 3/16 blue, 3/16 red, and 1/16 mauve.

Knowing that the phenotypic ratio is 9:3:3:1, we can assume that there are two genes involved in the flower color expression. We can name these genes B and R with a dominant and a recessive allele each (B, b and R, r respectively).

According to the first cross, we might establish the following genotypes:

1st Cross: blue-flowered plant x red-flowered plant

Parentals) BBrr x bbRR

Gametes) Br, Br, Br, Br bR, bR, bR, bR

F1) 100% BbRr, yellow plants

Parentals) BbRr x BbRr

Gametes) BR, Br, bR, br

BR, Br, bR, br

Punnett square) BR Br bR br

BR BBRR BBRr BbRR BbRr

Br BBRr BBrr BbRr Bbrr

bR BbRR BbRr bbRR bbRr

br BbRr Bbrr bbRr bbrr

F2) 9/16 yellow ---> 1/16 BBRR + 2/16 BBRr + 4/16 BbRr + 2/16 BbRR

3/16 blue ------> 1/16 BBrr + 2/16 Bbrr

3/16 red---------> 1/16 bbRR + 2/16 bbRr

1/16 mauve ----> 1/16 bbrr

So,

Yellow-flowered plants: BBRR, BBRr, BbRR, BbRr
Red-flowered plants: bbRR, bbRr
Blue-flowered plants: BBrr, Bbrr
Mauve-flowered plants: bbrr

According to these genotypes, the second cross would be like following,

2nd Cross: true-breeding red-flowered plants with true-breeding mauve flowered plants.

Parentals) bbRR x bbrr

Phenotype) Red Mauve

Gametes) bR, bR, bR, bR br, br, br, br

Punnett square) bR bR bR bR

br bbRr bbRr bbRr bbRr

F1) 100% bbRr, red flowered plants.

6 0

3 years ago

When egg white is heated, it hardens and is opaque. This cooking process cannot be reversed, but hard-boiled egg white can be di

marshall27 [118]

Answer:

Generally proteins are denatured at high temperature.Therefore when the egg is hard boiled they are denatured since eggs are protein, the 3-dimensional structure of protein is lost, and it is replaces with tangled meshwork of polypeptide chains .This is because the orderly arrangements of disulphide bonds in proteins are disrupted , which results in the formation of inter chains bonds among disulphide bonds, making the protein molecules to link together.This explains the reason for the 3-D structure disruption and formation of a macro molecule.

However, the addition of reducing agent , breaks the covalent disulphide bonds. While detergent breaks the interchain bonds among the disulphide bonds. (The noncovalent bonds),These combined effects untangled the mesh networks of polypeptides formed, and reduces the hardened nature,

Explanation:

5 0

2 years ago

1. They system that Linnaeus developed classifies organisms by ____.

marshall27 [118]

1.

C. Genus and species

Binominal nomenclature: a formal system of naming species of living things, such as humans which are <em>homo sapiens.</em>

2.

A. carbohydrates

any of a large group of organic compounds occurring in foods and living tissues and including sugars, starch, and cellulose.

3.

C. work with other cells

one unicellular organism would quickly die if was not within a colony of very similar unicellular organisms.

4.

C. Bacteria

bacteria are able to cause contagious diseases seeing as a virus, (which can be a contagious disease) is a form of bacteria.

4 0

3 years ago