Answer:
Time is 14.8 s and cannot landing
Explanation:
This is a kinematic exercise with constant acceleration, we assume that the acceleration of the jet to take off and landing are the same
Calculate the time to stop, where it has zero speed
Vf² = Vo² + a t
t = - Vo² / a
t = - 110²/(-7.42)
t = 14.8 s
This is the time it takes to stop the jet
Let's analyze the case of the landing at the small airport, let's look for the distance traveled to land, where the speed is zero
Vf² = Vo² + 2 to X
X = -Vo² / 2 a
X = -110² / 2 (-7.42)
X = 815.4 m
Since this distance is greater than the length of the runway, the jet cannot stop
Let's calculate the speed you should have to stop on a track of this size
Vo² = 2 a X
Vo = √ (2 7.42 800)
Vo = 109 m / s
It is conclusion the jet must lose some speed to land on this track
Answer:
5 Joules, 7.5 Joules and 10 Joules respectively
Explanation:
Potential energy due to gravity is given by mass*gravity*height or weight*height(As weight= mass*gravity)
The potential energy at the height of 1 meters = 5*1 = 5 Joules
The potential energy at the height of 1.5 meters = 5*1.5 = 7.5 Joules
The potential energy at the height of 2 meters = 5*2 = 10 Joules
Answer:
It would take 1 s to hear the echo.
Explanation:
Here, the sound covered a total of 340 meters, since it bounces off the canyon wall and travels back to Miles in the form of echo.
The time elapsed can be determined by,
v =
⇒ t =
where: v is the speed of sound in air (343 m/s), D is the distance of the nearest canyon (170 m).
So that,
2D = 2 x 170 = 340 m
Thus,
t =
= 0.9913 s
t = 1 s
It takes 1s for Miles to hear his echo.
Answer:
Word for the first blank: gravity
Word for the second blank: matter
Explanation:
The only way debris from the impact with Earth can be held close to Earth is due to a force. The only force that could be acting from Earth is "the force of gravity".
The gravitational pull of this new object being formed, increases proportional to its mass as more and more "matter" accumulates. And the accretion process is now on its way.
Answer:
1) The girl's acceleration at time 't' is, m/s²
2) The girl's acceleration at time 't₁' is, m/s²
3) The girl's acceleration at time 't₂' is, m/s²
Explanation:
Given data,
The initial walking speed of the girl, u = 0
The speed of the girl at the time 't' 3 s is, v₁ = 1.4 m/s
The time period the girl walked at the speed 1.4 m/s is, t₁ = 6 s
The girl slows down and comes to a stop during a period, t₂ = 10 s
1) The girl's acceleration at time 't'
m/s²
2) The girl's acceleration at time 't₁'
m/s²
3) The girl's acceleration at time 't₂'
m/s²