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3 years ago

What does properties mean

Physics

1 answer:

OleMash [197]3 years ago

7 0

Answer:

a thing or things belonging to someone; possessions collectively.

Explanation:

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A piston in an internal combustion engine applies torque during 150° of each full rotation of the crankshaft to which it is conn

aalyn [17]

Answer:

T=1.566 N.m

Explanation:

Given that:

rotational speed of the scrank shaft, N = 2500 rpm

power produced by one cylinder, P = 410 W

We know, in case of rotational power:

$P=\frac{2\pi.N.T}{60}$

where: T= torque

Substituting the respective values in the above eq.

$410=\frac{2\pi\times2500\times T}{60}$

$T= \frac{410\times60}{2\pi\times2500}$

T=1.566 N.m is the torque applied by the each piston of the engine.

4 0

3 years ago

Calculate the potential energy stored in an object of mass 50 kg at a height of 20 m from the ground.

bearhunter [10]

Answer:

potential energy=mgh

=50×10×20

=10000 J

8 0

3 years ago

Read 2 more answers

For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 6.85 105 N. What is the m

Leviafan [203]

Answer:

The magnitude of the resistive force exerted by the water is $6.85\times 10^{5}$ newtons.

Explanation:

By First and Second Newton's Law, the resistive force exerted by the water on the cruise ship has the same magnitude of forward thrust, with which it is antiparallel to. The equation of equilibrium for the luxury liner is:

$\Sigma F = F-R = 0$ (Eq. 1)

Where:

$F$ - Forward trust, measured in newtons.

$R$ - Resistive force exerted by the water, measured in newtons.

From (Eq. 1), we get that: ( $F = 6.85\times 10^{5}\,N$ )

$R = F$

$R = 6.85\times 10^{5}\,N$

The magnitude of the resistive force exerted by the water is $6.85\times 10^{5}$ newtons.

4 0

3 years ago

during a workout, a football player pushes a blocking dummy a distance of 30 m. while pushing the dummy the same distance a seco

babymother [125]

$Power=\frac{Work}{Time}=\frac{Force\times distance}{time}$

If he wants to increase power, force must increase and decrease time.

8 0

3 years ago

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You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N while the opposing force of

Rzqust [24]

Answer:

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

= 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

<u>Therefore the work of the 1.55N 3.36J</u>

4 0

3 years ago