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3 years ago

3(4+3)^2 -11= ????????????

Mathematics

1 answer:

yan [13]3 years ago

7 0

Answer:

136 is the answer

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(CORRECT GETS BRAINLIEST) A scale drawing of a house shows the house has a height of 11.5 inches. If the scale is 1 inch = 3 fee

lesantik [10]

Answer:

34.5 ft

Step-by-step explanation:

1 = 3

11.5 x 3 = 34.5

6 0

3 years ago

1) Which number has the least value? A. 87.4 B. 7.48 C. 8.74 D. 4.78

lutik1710 [3]

D has the least value

5 0

3 years ago

Read 2 more answers

(x+y)² + 2(x+ y)(x- y) + (x– y)²

densk [106]

Answer:

2x(x+y)(x-y)

Step-by-step explanation:

Given the expression;

(x+y)² + 2(x+ y)(x- y) + (x– y)²

Factorize

(x+y)² + (x+ y)(x- y) + (x+ y)(x- y) + (x– y)²

= (x+y)[x+y+(x-y)] +(x-y)[(x+y)+(x-y)]

= (x+y)(x-y)(x+y+(x-y))

= (x+y)(x-y)(x+y+x-y)

= (x+y)(x-y)(2x)

hence the expanded form is 2x(x+y)(x-y)

6 0

3 years ago

Cora says he dosen't need to know the y-interce of a line to write its equation,just its slope and some other point on the line.

Soloha48 [4]

Answer:

Yes, Cora is correct.

The equation of line with point (2,6) and slope of line (-1/3)

is x + 3y - 20 = 0

Step-by-step explanation:

Yes, the equation of a line can be written using a point and a slope of the line equation.

Cora has used the POINT SLOPE FORMULA, to represent the line equation.

In Point Slope formula:

The equation with slope m and points (x0,y0) can be written as:

(y-y0) =m (x-x0)

Here, the point (x0,y0) = (2,6)

and slope m = (-1/3)

So, the equation can be written as: $( y - 6) =\frac{-1}{3} (x-2) \\\implies 3( y-6) = (2-x)\\or, 3y - 18 -2 + x = 0\\or, x + 3y - 20 = 0$

Hence, the equation of line with point (2,6) and slope of line (-1/3)

is x + 3y - 20 = 0

4 0

3 years ago

Area and perimeter of geometric functions

SCORPION-xisa [38]

Answer:

C. 60

Step-by-step explanation:

From triangle ADB,

$|AD|^2+|BD|^2=|AB|^2$

$|AD|^2+16^2=20^2$

$|AD|^2=20^2-16^2$

$|AD|^2=400-256$

$|AD|^2=144$

$|AD|=\sqrt{144}$

$|AD|=12$

From triangle ADC,

$|CD|^2+12^2=15^2$

$|CD|^2+144=225$

$|CD|^2=225-144$

$|CD|^2=81$

$|CD|=9$

The perimeter is the distance around the figure.

The perimeter

$=15+20+16+9$

$=60$

8 0

4 years ago

Read 2 more answers