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coldgirl [10]
4 years ago
8

Determine whether the sequence converges or diverges. If it converges, give the limit: 72, 18. 9/2, 9/8, ...

Mathematics
1 answer:
kakasveta [241]4 years ago
7 0
Answer: The sequence converges. The limit it converges to is 0.

-------------------------------------------------------------------------------------------

The sequence is a geometric sequence with a = 72 and r = 1/4. Because 0 < r < 1, this means that the sequence gets smaller and smaller. The terms get closer to 0. They don't actually get there but the limiting value is 0. 
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A rectangular sign is 4 times its width if the perimeter is 20 inches what is the signs area.
zvonat [6]

Answer: 1,600 cubic inches

Step-by-step explanation: 20x4=80 multiply both sides 80x20=1,600 cubic inches

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3 years ago
Identify an equation in slope-intercept form the line parallel to y=-3x+7that passes through (2,-4)
gregori [183]

Answer:

y=-3x+2

Step-by-step explanation:

Same slope = parallel. You can aso double check this answer by either graphing using the desmos online graphing calculator or by plugging in the point into the equation y = -3(2) + 2 --> y = -6 + 2 --> y = -4, so we are correct.

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Step-by-step explanation:

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3 years ago
What is the greatest common factor of 21 40
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3 years ago
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A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
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