Can someone please help me out here? :)

LOTS OF POINTS IM DESPERATE! can someone please refresh my memory on a couple of log equations? Thank you!

n200080 [17]

Answer:

78. t=8.66yrs

79. r=23.10%

80. r=11.0975%

Step-by-step explanation:

78. Given the initial deposit is $1,000 and the 8% compounded continuously. The doubling time can be calculated using the formula;

$A=Pe^{it}$

Given that A=2P, we substitute in the equation to solve for t:

$A=Pe^{rt}\\\\2P=Pe^{rt}\\\\2=e^{0.08t}\\\\0.08t=\ In 2\\\\t=8.66\ years$

Hence, it takes 8.66 years for $1,000 to double in value.

79.

Given the initial deposit is $1,000 and the r% compounded continuously.

-The doubling rate can be calculated using the formula;

$A=Pe^{rt}$

#We substitute our values in the equation to solve for r:

$A=Pe^{rt}\\\\A=2P, t=3\\\\\therefore\\\\2P=Pe^{3r}\\\\2=e^{3r}\\\\r=\frac{In \ 2}{3}\\\\=0.23105\approx 23.10\%$

Hence, the deposit will double in 3 years at a rate of 23.10%

80.

Given the initial deposit is $30,000 and the future value is $2,540,689.

-Also, given t=40yrs, the rate of growth for continuous compounding is calculated as:

$A=Pe^{rt}, \ \ \ r=r, t=40yrs\\\\2540689=30000e^{40r}\\\\\frac{2540689}{30000}=e^{40r}\\\\r=\frac{In \ (2540689/30000)}{40}\\\\\\=0.110975=11.0975\%$

Hence, the deposit will grow at a rate of approximately 11.0975%

3 0

4 years ago

The endpoints of one diagonal of a rhombus are (0, -8) and (8, -4). If the coordinates of the 3rd vertex are (1, 0), what are th

xeze [42]

The answer is (-7, -12).

Attached is the graph to show the answer.

4 0

3 years ago

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Geometry

Vesnalui [34]

The first two graphs are D) and D).
For the last one (above), the triangles are not congruent (D), because C --> C' doesn't follow the same translation rule as A, B --> A', B'

4 0

4 years ago

Which statement describes the graph

Andrews [41]

What graph, bro? I need a picture to see what I have to solve here.

7 0

3 years ago

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Which statements are true for verifying the solution set of StartAbsoluteValue negative 2 x + 8 EndAbsoluteValue less-than 12 as

mariarad [96]

Answer:

I had to go back and double check, this was kind of confusing asking if saying this statement is true or false is true or false. So keep your eye on that. as long as x is between (but not equal to) -2 and 10 then the inequality is true. Fromt here you have to see if the option is SAYING it is true or not.

Step-by-step explanation:

I am assuming this is saying |-2x+8|<12 as -2 < x < 10

Substituting 10 for x into the original inequality will create a false statement.

True, since x has to be explicitly LESS THAN 10, not equal

Substituting 6 for x into the original inequality will create a false statement.

False, 6 is greater than -2 and less than 10

Substituting 20 for x into the original inequality will create a true statement.

False, greater than 10

Substituting –20 for x into the original inequality will create a false statement.

True. Kinda confusing since it is asking if it is a false statement. It is TRUE that it is a false statement.

Substituting –10 for x into the original inequality will create a true statement.

False, x needs to be between -2 and 10 (explicitly between and not equal to) to be true.

Substituting 0 for x into the original inequality will create a true statement

True, it is between -2 and 10

8 0

3 years ago

Read 2 more answers