Step-by-step explanation:
Here Given
Total counters = 81
red counters are 9 more than the yellow ones.
And Yellow counter = blue counter
So let the Yellow counter be x and as blue counter and yellow counter are same then blue counter will be also x
And by the question
Red counter = 9 + x
Now
9 + x + x + x = 81
9 + 3x = 81
3x = 81 - 9
3x = 72
x = 72 / 3
Therefore x = 24
Now
Red counters = 9 + 24 = 33
Blue counters = 24
Yellow counters = 24
Hope it helped :)
We know that
We can write an Arithmetic Sequence as a rule:
<span>an = a1 + d(n−1)</span>
where
<span>a1 = the first term
<span>d =the "common difference" between terms
in this problem
a1=15 a2=7 a3=-1 a4=-9 ..... an=-225
d=a2-a1
d=7-15-----> d=-8
</span></span>an = a1 + d(n−1)
for
an=-225
d=-8
a1=15
find n
-225=15+(-8)*(n-1)--> (n-1)=[-225-15]/-8----> n-1=30---> n=30+1---> n=31
the answer is31
3px = 2q(r-5x)
distribute
2qr - 10qx
3px = 2qr - 10qx
To solve for x
add 10qx to both sides
3px + 10qx = 2qr
factor out x
x(3p+10q) = 2qr
divide both sides by 3p+10q to isolate x
x = 2qr / <span>(3p+10q)
Hope this helps :)</span>
That's easy if there is 100 chairs there would be 10 rows with ten chairs in each row
