Answer:
Step-by-step explanation:
Given expression is:
![(\sqrt[8]{x^7} )^{6}](https://tex.z-dn.net/?f=%28%5Csqrt%5B8%5D%7Bx%5E7%7D%20%29%5E%7B6%7D)
First we will use the rule:
![\sqrt[n]{x} = x^{\frac{1}{n} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D)
So for the given expression:
![\sqrt[8]{x^{7}}=(x^{7} )^{\frac{1}{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bx%5E%7B7%7D%7D%3D%28x%5E%7B7%7D%20%29%5E%7B%5Cfrac%7B1%7D%7B8%7D%20%7D)
We will use tha property of multiplication on powers:
Applying the outer exponent now
Answer:
Step-by-step explanation:
Answer
D
Hope this help you?
1 <span>Set up the long multiplication.
</span>
<span><span>543</span><span>x36</span></span>
2 <span>Calculate 3 x 6, which is 18.
Since 18 is two-digit, we carry the first digit 1 to the next column.
</span>
3 <span>Calculate 4 x 6, which is 24. Now add the carry digit of 1, which is 25.
Since 25 is two-digit, we carry the first digit 2 to the next column.
</span>
4 <span>Calculate 5 x 6, which is 30. Now add the carry digit of 2, which is 32.
Since 32 is two-digit, we carry the first digit 3 to the next column.
</span>
5 <span>Bring down the carry digit of 3.
</span>
6 <span>Calculate 3 x 3, which is 9.
</span>
7 <span>Calculate 4 x 3, which is 12.
Since 12 is two-digit, we carry the first digit 1 to the next column.
</span>
8 <span>Calculate 5 x 3, which is 15. Now add the carry digit of 1, which is 16.
Since 16 is two-digit, we carry the first digit 1 to the next column.
</span>
9 <span>Bring down the carry digit of 1.
</span>
10 <span>Calculate 3258 + 16290, which is 19548
</span>
11 <span>Therefore, 543 x 36 = 19548.
</span><span>
The answer is B.19548</span>
