The first shaded triangle is 144 cm.
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
c = 20 ft
Step-by-step explanation:
The largest square will be 14 sqrt(2) ft long
To figure out the side length of the square
use the pythagorean theorem
a^2 + b^2 =c^2
we are limited by the shortest side of the rectangle
28 ft
each side of the triangle is 1/2 the length of the short side of the rectangle or 14 ft
a^2 + b^2 =c^2
14^2 + 14^2 = c^2 where c is the side of the square
196 + 196 = c^2
392 = c^2
take the square root of each side
sqrt(392) = sqrt(c^2)
c = 14sqrt(2)
c = 19.799ft
to the nearest whole number
c = 20 ft
The answers would be pyramid and triangular prism.
Answer:
168cm is the right answer
Step-by-step explanation: