Ask question

Ask question

All categories

3 years ago

9

Mike rented a truck for one day. There was a base fee of $17.99, and there was an additional charge of 83 cents for each Mike dr

iven. Mike had to pay $140 when he returned the truck. For how many miles did he drive the truck?

1 answer:

Vesna [10]3 years ago

3 0

17.99 + 0.83m = 140
0.83m = 140 - 17.99
0.83m = 122.01
m = 122.01 / 0.83
m = 147 <== Mike drove 147 miles

You might be interested in

You practice your basketball shots every day. On Friday you made 20 shots. On Saturday you made 16 shots. What is the percent de

STatiana [176]

So,

All you have to do to find the percent decrease is to subtract your score on Saturday from your score on Friday and divide the result by your score on Friday. If you let "f" represent your score on Friday and let "s" represent your score on Saturday, you can re-write this mathematically:

$\frac{f - s}{f} = percent\ decrease$

Substitute.
$\frac{20 - 16}{20} = percent\ decrease$
$\frac{4}{20} \ or\ \frac{1}{5}\ or\ twenty\ percent = percent\ decrease$

The percent decrease in shots you made was 20%. That would be option C.

8 0

3 years ago

Read 2 more answers

1. What term means "per hundred"?

Romashka-Z-Leto [24]

Percent. Hope this helps!

5 0

3 years ago

Read 2 more answers

A taxi service charges $5.00 to ride in the vehicle and then $1.00 for each mile.

nikitadnepr [17]

Answer:76

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

How many words can be formed by using the W,X,Y,Z if repetitions is not allowed?

Setler [38]

Answer:

24

Step-by-step explanation:

What you have here is a permutation, seeing as each element can only be used once.

We have 4 letters initially, so we can choose any 1 as our first letter. We have 4 choices for our first letter

However, once we choose our first letter, we can't use it anymore, so, for our second letter, we can only choose from the remaining 3 letters.

Furthermore, once we choose our second letter, we can only choose our 3rd letter from the remaining two letters we didn't choose yet.

Finally, our last letter will always be the one we didn't choose the last 3 times. So there is only one choice here.

Going off of this, we have four choices for the 1st letter, three choices for the 2nd letter, two choices for the 3rd letter, and one choice for the 4th letter

The way to calculate how many permutations we have without repetition is using factorials

N!

Where N is the number of elements you have.

In this case, it would be 4!

4! is 4 * 3 * 2 * 1

Which equals 24

If you notice, each number in 4! is the number of options we have for each choice. 4, then 3, and so on

5 0

3 years ago

What is the place value for 3 in 6,035

bonufazy [111]

The place value in 6,035 is 30

5 0

3 years ago