1) expand the brackets
6(-3 - x) - 2x = 14
-18 - 6x - 2x = 14
simplify
-18 - 8x = 14
then add 18 to both sides to get the x's on there own
-8x = 32
then divide by -8
x = 32/-8
x = -4
2) multiply everything by 7x
2 + (6 x 7x) + ( 17x × 7x) = 18 x 7x
2 + 42x + 119x^2 = 126x
put everything on one side
119x^2 - 84x + 2 = 0
then use quadratic equation to solve
x = 0.024671849 or 0.6812105039
Answer:
The surface area of the square pyramid if the slant height is 13mm and the base length is 11mm is 407 sq.mm.
Step-by-step explanation:
Slant height of square pyramid = l = 13 mm
Base length of square pyramid = b = 11 mm
Formula of surface area of square pyramid =
Substitute the values in the formula :
Surface area of square pyramid =
Surface area of square pyramid =407 sq.mm.
Hence the surface area of the square pyramid if the slant height is 13mm and the base length is 11mm is 407 sq.mm.
Well I would say yes because when you cut the larger fraction in half the numbers came up with are 2/4 and so with that mentioned the fractions are equivalent. I hoped that this helped. :)
Answer:
57 days
Step-by-step explanation:
Given that:
t(0) = 26000
Growth rate (S'(t)) = 80t^1/2
Targeted number of subscribers = 49000
Take the integral of the growth rate :
∫80t^1/2dt = [(80t^(1/2 + 1)) / 1/2 + 1] + C
[(80t^(1/2 + 1)) / 1/2 + 1] + C = (80t^3/2) / 3/2 + C
(80t^3/2) * 3/2 + C = (160/3)t^3/2 + C
(160/3)t^3/2 + C
Let C = t(0)
(160/3)t^3/2 + 26000 = 49000
(160/3)t^3/2 = 49000 - 26000
(160/3)t^3/2 = 23000
Multiply both sides by 3/160
t^3/2 = 23000* 3/160
t^3/2 = 69000/160
t^3/2 = 431.25
t^(3/2 * 2/3) = 431.25^2/3
t = 57.080277
t = 57 days (approx.)
Answer:
[ 250 , 282 ]
Step-by-step explanation:
A Normal Distribution N ( 0,1)
We know one of the characteristics of a normal distribution is the symmetry and the fact that in the interval of
μ₀ - σ and μ₀ + σ are found the 95.5 % of all values
In our case we have μ₀ = 266 and the standard deviation σ = 16
So μ₀ - σ ⇒ 266 - 16 = 250 the lowest value for the interval and
μ₀ + σ ⇒ 266 + 16 = 282 the highest value for the interval
The interval with 95.5 % of all values is
[ 250 , 282 ]