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Elza [17]
3 years ago
6

Could somone help me please??? for 12 points​

Mathematics
1 answer:
pentagon [3]3 years ago
7 0

there is an error because -9 x 1 = -9 not -1. But I would assume that you multiply -9×-1 and then -9×-2 ect.

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Can someone solve 5 + 2x = + 6<br><br> and n - 3n = 14 - 4n<br><br> and 7 ( 5a - 4 ) - 1 = 14 - 8a
professor190 [17]

Answer:

5 + 2x = 6

2x = 6-5

2x = 1

x = 0.5

n -3n = 14 -4n

-2n = 14-4n (since 4n is negative, change the sign to make it positive and then add 4n to both sides of the equation)

2n = 14

n = 7

7 (5a - 4) - 1 = 14 - 8a

35a - 28 - 1 = 14 -8a

35a -29 = 14 - 8a

43a = 43

a = 1

6 0
3 years ago
Read 2 more answers
Consider two vectors A and B A=14i and B= -4i+8j
DaniilM [7]
Assuming \mathbf a,\mathbf b\in\mathbb R^3, you have

\mathbf a\cdot\mathbf b=(14)(-4)+(0)(8)=-56

so

((\mathbf a\cdot\mathbf b)\,\mathbf i)\cdot\mathbf a=(-56\,\mathbf i)\cdot(14\,\mathbf i)=(-56)(14)=-784

Next,

\mathbf a+\mathbf b=(14\,\mathbf i)+(-4\,\mathbf i+8\,\mathbf j)=10\,\mathbf i+8\,\mathbf j

Then

(\mathbf a+\mathbf b)\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\10&8&0\\-4&8&0\end{vmatrix}=112\,\mathbf k

((\mathbf a+\mathbf b)\times\mathbf b)\times\mathbf k=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&112\\0&0&1\end{vmatrix}=\mathbf 0
4 0
3 years ago
Can someone answer this asap?
IgorLugansk [536]

Answer:

145

Step-by-step explanation:

six can go into eight once with a remainder of two, next you bring down the seven and you will get twenty seven, six can go into twenty seven four times six by four is 24,27 take away 24 is 3 then you bring down the one, six can go into 31 five times, six by five is 30, 31 take away 30 is one

5 0
3 years ago
Which posulate proves the two triangles are congruent?
san4es73 [151]

Answer:

D ASA

Step-by-step explanation:

ASA

5 0
2 years ago
Solve the inequality -55x/2-10&gt;-185/2
inessss [21]
The solution to the problem is x < 31/55
6 0
3 years ago
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