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3 years ago

Could somone help me please??? for 12 points

Mathematics

1 answer:

pentagon [3]3 years ago

7 0

there is an error because -9 x 1 = -9 not -1. But I would assume that you multiply -9×-1 and then -9×-2 ect.

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Can someone plz help me with this one problem plzzzzz I’m marking brainliest!!!

luda_lava [24]

Answer:

1st

Step-by-step explanation: i think

5 0

3 years ago

Read 2 more answers

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m

Marta_Voda [28]

Answer:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

Step-by-step explanation:

Assuming the following dataset:

Speed 42-45 46-49 50-53 54-57 58-61

Freq. 21 15 6 4 2

And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

$\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}$

And is useful construct a table like this one:

Speed Freq Midpoint Freq*Midpoint

42-45 21 43.5 913.5

46-49 15 47.5 712.5

50-53 6 51.5 309

54-57 4 55.5 222

58-61 2 59.5 119

Total 48 2276

And the mean is given by:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

6 0

3 years ago

A business was valued at £80000 at the start of 2013. In 5 years the value of this business raised to £95000. this is equivalent

dedylja [7]

Answer:

20%

Step-by-step explanation:

Value increased in 5 years = £95000 - £80000 = £5000

Value increase in 1 year =5000/5 = 1000

Increase % = (1000/5000 ) * 100 = (1/5) *100 = 20%

6 0

3 years ago

A rectangular aquarium 3 ft. x 2 ft. 1 ft. is 2/3 full of water. In cubic feet, how much water is in the tank

tatuchka [14]

To find the volume of a rectangular prism, we must multiply the length * width * height.

In this case,

Volume = 3 ft * 2 ft * 1 ft

= 6 ft^3

Because this tank is 2/3 full with water, to find out how much water is in the tank, we must multiply 2/3 by the total volume of the tank (6 ft^3).

2/3 * 6 ft^3 = 4 ft^3

This means that there are 4 cubic feet of water in the tank.

Hope this helps!

6 0

3 years ago

For the function f(x) = 7/2x-16, what is the difference quotient for all nonzero values of h?

sergey [27]

Answer:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}$

Step-by-step explanation:

Given

$f(x) = \frac{7}{2}x - 16$

Required

The difference quotient for h

The difference quotient is calculated as:

$\frac{f(x + h) - f(x)}{ h}$

Calculate f(x + h)

$f(x) = \frac{7}{2}x - 16$

$f(x+h) = \frac{7}{2}(x+h) - 16$

$f(x+h) = \frac{7}{2}x+ \frac{7}{2}h- 16$

The numerator of $\frac{f(x + h) - f(x)}{ h}$ is:

$f(x + h) - f(x) = \frac{7}{2}x+ \frac{7}{2}h- 16 -(\frac{7}{2}x - 16)$

$f(x + h) - f(x) = \frac{7}{2}x+ \frac{7}{2}h- 16 -\frac{7}{2}x + 16$

Collect like terms

$f(x + h) - f(x) = \frac{7}{2}x -\frac{7}{2}x + \frac{7}{2}h- 16 + 16$

$f(x + h) - f(x) = \frac{7}{2}h$

So, we have:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h \div h$

Rewrite as:

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h * \frac{1}{h}$

$\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}$

5 0

2 years ago

Could somone help me please??? for 12 points​

Could somone help me please??? for 12 points