Lenny is offered jobs at two different companies. At company A, he gets a base salary of $55,000 with manual raises of $2500. At
company B, he gets a base salary of $62000 with annual raises of $2000. A. How many years will it take for Lenny make the same salary at both companies?
B. If Lenny decides that he will work 20 years on his job, which company should he go to? Explain
Before answering these questions, we need to write out both equations. For Job 'A', his salary would be: 55,000 + 2,500n This assumes 'n' equals the number of years Lenny spends at these companies. For Job 'B', his salary would be: 62,000 + 2,000n
A. So basically we need to find a number were: 55,000 + 2,500n = 62,000 + 2,000n is true. So basically solve ^that^ equasion. 55,000 + 2,500n = 62,000 + 2,000n simplify 500n = 7,000 devide n = 14 Fourteen years is your answer.
B. a. 55,000 + 2,500n b. 62,000 + 2,000n So in order to answer this question, you basically just have to replace 'n' with the number '20', and see which one's bigger. a. 55,000 + 2,500(20) 55,000 + 50,000 105,000 b. 62,000 + 2,000(20) 62,000 + 40,000 102,000 105,000 > 102,000 So your answer is: Lenny should go to company 'a' because 105,000 is greater than 102,000. [[tip: If you want to wow, surprise, or confuse your teacher (depending on her actual intelligence) write something like, 'another reason Lenny should choose company 'a' is because it gives higher annual raises, which is better in long-term.' He/She may not get it though, lol, wrong class.]]
The actual is 60 feet long, the drawing is only 1 foot long. So the scale factor must be 1/60. You know that the scale factor has to be less than one in this case because you're going from a bigger measurement to a smaller measurement(60 to 1).
