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Ipatiy [6.2K]
3 years ago
14

Which sounds better, a cassette or vinyl???

Computers and Technology
1 answer:
katen-ka-za [31]3 years ago
5 0
A vinyl . I hope I helped !
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10 points
Bingel [31]

Answer:

cool this is cool

Explanation:reEEEEEEE

6 0
3 years ago
All conductors,buses,and connections should be considered
SashulF [63]

They should be considered as energized

6 0
4 years ago
Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
Why is the human immunodeficiency virus so deadly?
damaskus [11]

<em> </em><em>I</em><em> </em><em>think</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>D</em><em>.</em>

<em>It</em><em> </em><em>kills</em><em> </em><em>the</em><em> </em><em>cells</em><em> </em><em>that</em><em> </em><em>make</em><em> </em><em>antibodies</em><em>.</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em>

8 0
3 years ago
Two stations running TCP/IP are engaged in transferring a file. This file is 1000MB long, the payload size is 100 bytes, and the
weeeeeb [17]

Answer:

a. 2100

b. 2199

Explanation:

GIven that:

The file size = 1000 MB

The  payload size is  = 100 bytes

The negotiated window size is = 1000 bytes.

This implies that the sliding window can accommodate maximum number of 10 packets

The sender receives an ACK 1200 from the receiver.

Total byte of the file is :

1000 MB = 1024000000 bytes

a.

Sender receives an ACK 1200 from the receiver but still two packets are still unacknowledged

=1200 + 9 * 100

= 1200 +  900

= 2100

b. What is the last byte number that can be sent without an ACK being sent by the receiver?

b. Usually byte number starts from zero, in the first packet, the last byte will be 99 because it is in 1000th place.

Thus; the last byte number send is :

= 1200 + 10 *100 -1

= 1200 + 1000-1

= 1200 + 999

= 2199

6 0
4 years ago
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