Answer:
Customer(1) - (1) Vehicle.
Explanation:
Cardinality is the mapping of entities or group of entities to a cardinal value. It tries to show the relationship between two objects like a cups in a shelf or plates in racks.
The car dealer in the question, sells one car to a customer and keep or prioritise the record of the main owner of the acquired vehicle. So the maximum cardinality assignment of the customer and vehicle is one (1) to one (1) mapping.
Answer:
CASE
Explanation:
Case Structure is a mechanism that allows different executions when there are several distinct possible values for a single variable, and each value requires a different subsequent action depending on the value of the label.
Case structure is also a conditional control structure that appears in most modern programming languages and allows a selection to be made between several sets of program statements.
It sounds like you are looking for a network. If a node can not find a network to connect to, then it cannot connect.
Edge computing be used to increase sustainability With Edge Computing the number of records traversing the network can be reduced greatly, freeing up bandwidth.
<h3>How is part computing sustainable?</h3>
Data centers devour an expected 2 hundred terawatt-hours (TWh) of power every year–extra than the power intake of a few countries. They additionally produce an expected 2% of all worldwide CO2 emissions. Edge Computing reduces network site visitors and records centre usage.
Data centres devour an expected 200 terawatt-hours (TWh) of power every year–extra than the power intake of a few countries. They additionally produce an expected 2% of all worldwide CO2 emissions.
Read more about the sustainability:
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Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
