Answer: The goals of computer security are to protect computers and users from data theft or loss as well as damage to any part of the computer.
Explanation: Common means of achieving computer security are firewalls, anti-virus software and this can fail due to hardware problems or
weaknesses that prevent malicious attacks.
To answer this question, think of a time when you experienced any one of these. For example, personally, I was once an unfortunate victim of a general malicious attack that took advantage of a weakness in my anti-virus software. After clicking on a link on a dodgy website, a virus was installed on my computer. My computer finally crashed, without any hope of restarting it. I lost all my data and I had to buy a new computer. This was a malicious attack.
However, sometimes people can be specifically targeted to steal their data or monitor their activities.
Answer:
Automation testing can be used for:
<u>Input-output test
:</u> If the main function of your software is to transform input data into output data you can configure a new test by providing a new input/output pair, then the test will check to see if the output matches with the expected values.
<u>Unit test
:</u> This test is a script to check the return values of a specific code by initializing it and calling his methods. This is a part of a test-driven development process.
<u>Integration test
:</u> This test is a code level script that does a complete check process involving multiple objects. For example, you might make a test for “buy a product” which checks to see if the database is updated, if the data is correct of the person is correct, and if the person placing the order gets the right confirmation email.
<u>Smoke Tests:</u> This test is executed immediately after implementation on production to ensure that the application is still functioning.
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
Answer:
I would get rid of the machine and well
