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3 years ago

I need to know how to solve it

Mathematics

2 answers:

Wewaii [24]3 years ago

8 0

I think first you should 7-42 then you will get -35 which will be -7x-35. I hope that I was helpful

Snowcat [4.5K]3 years ago

3 0

-7x > -42. So you divide on both sides by -7 and that gives you x > 6

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Help please, will give lots of points!

Troyanec [42]

Step-by-step explanation:

roots as exponents are fractions

if there is no root number next to the radical sign its assumed that its 1/2

3√2 is 2^(1/3)

√3 is 3^(1/2)

4√3 is 3^(1/4)

5√2 is 2^(1/5)

8 0

2 years ago

Tyrone is buying candy by the pound to stuff into a piñata. Her purchased 14 pounds of candy for $12. How much is the cost of on

Deffense [45]

I believe the answer is

26

sorry if wrong

if not an answer choice then 168.

4 0

3 years ago

Solve equation (n-1)(n+6)(n+5)=0

Vika [28.1K]

Answer:
1, -6 and -5

Explanation:
To solve the equation means to get the values of n which satisfy the given equation.
The equation given is:
(n-1) (n+6) (n+5) = 0
This equation will be true if any of the terms (brackets) is equal to zero.
This means that:
either n-1 = 0 .............> n = 1
or n + 6 = 0 ................> n = -6
or n + 5 = 0 ................> n = -5

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Add the following values.<br> (2.1 × 1016) + (3.2 × 1015)

qwelly [4]

Answer:

5381.6

Step-by-step explanation:

$(2.1 × 1016) + (3.2 × 1015)$

$= 5381.6$

8 0

2 years ago

Plz help<br>urgent !!!!<br>will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

7 0

3 years ago