Answer:
Step-by-step explanation:
Okay, so the equations would be:
x + 3y = 24
3y + 5x = 36
Imma use Substitution to solve this:
x = -3y + 24
3y + 5(-3y + 24) = 36
3y - 15y + 120 = 36
-12y + 120 = 36
-12y = -84
y = 7
x = -3(7) + 24
x = -21 + 24
x = 3
So the first number (x) would be 3 and the second number (y) would be 7.
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
