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4 years ago

I don't know how to solve it?

Mathematics

2 answers:

Law Incorporation [45]4 years ago

8 0

2/4+2/4=4/8 And 8×4=32 same as 8+8=16
16+16=32 its that easy

Grace [21]4 years ago

3 0

Just turn 5/6ths into x/32nds. For example I could turn 1/2 into 2/4. And 2/4 into 4/8.

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The company is going to choose three rows in each section to win the hats. There are 46 rows in a

jeka94

Answer:

$\frac{43}{46}$

Step-by-step explanation:

3 out of 46 rows are going to win, meaning that 43 out of 46 rows are not going to win

Make that a fraction:

$\frac{43}{46}$

7 0

2 years ago

A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

3 0

3 years ago

In triangle $ABC$, the angles $\angle A$, $\angle B$, $\angle C$ form an arithmetic sequence. If $\angle A = 23^\circ$, then wha

LenKa [72]

Answer:

$97^0$

Step-by-step explanation:

Given that the angles A, B, C in a Triangle form an arithmetic sequence where A=23 degrees.

The nth term of an Arithmetic sequence is given by the formula: $T_n=a+(n-1)d$

Where:

a=first term

n=number of term

d=common difference

In this case,

$Angle \:A, a=23^0$

$Angle B, T_2=23+(2-1)d=(23+d)^0\\Angle C, T_3=23+(3-1)d=(23+2d)^0$

The sum of angles in a triangle is 180 degrees. Therefore:

∠A+∠B+∠C=180 degrees

$23^0+(23+d)^0+(23+2d)^0=180\\69^0+3d=180^0\\3d=180^0-69^0\\3d=111^0\\d=37^0$

Therefore:

Angle C,

$(23+2d)^0=(23+2(37))^0=23+74\\C=97^0$

6 0

3 years ago

A square has a vertex at (-15,-9) and is dilated at the origin with a scale factor of 1/3. What is the new coordinate of the ver

dangina [55]

Answer:

Step-by-step explanation:

6 0

3 years ago

Using fermat's little theorem, find the least positive residue of $2^{1000000}$ modulo 17.

torisob [31]

Fermat's little theorem states that
$a^p$ ≡a mod p

If we divide both sides by a, then
$a^{p-1}$ ≡1 mod p
=>
$a^{17-1}$ ≡1 mod 17
$a^{16}$ ≡1 mod 17

Rewrite
$a^{1000000}$ mod 17 as
$=(a^{16})^{62500}$ mod 17
and apply Fermat's little theorem
$=(1)^{62500}$ mod 17
=>
$=(1)$ mod 17

So we conclude that
$a^{1000000}$ ≡1 mod 17

6 0

4 years ago